Termination Proof Script

Consider the TRS R consisting of the rewrite rules
1:    a__c  → a__f(g(c))
2:    a__f(g(X))  → g(X)
3:    mark(c)  → a__c
4:    mark(f(X))  → a__f(X)
5:    mark(g(X))  → g(X)
6:    a__c  → c
7:    a__f(X)  → f(X)
There are 3 dependency pairs:
8:    A__C  → A__F(g(c))
9:    MARK(c)  → A__C
10:    MARK(f(X))  → A__F(X)
The approximated dependency graph contains no SCCs and hence the TRS is trivially terminating.
Tyrolean Termination Tool  (0.00 seconds)   ---  May 3, 2006